In Sabarmati Express, there are as many wagons as the number of seats in each wagon and not more than one passenger can have the same berth (seat). If the middlemost compartment carrying 25 passengers is filled with 71.428% of its capacity, then find the maximum no. of passengers in train that can be accommodated if it has minimum 20% seats always vacant.

(a) 500

(b) 786

(c) 980

(d) Can’t be determined

**Ans**: (c) 980

**Explanation**:

No of wagon = No of seats in each wagon

We know, \displaystyle\frac{1}{14} = 7.1428\%

\qquad \Rightarrow71.428\% = \displaystyle\frac{10}{14} = \displaystyle\frac{5}{7}

71.428\% = \displaystyle\frac{5}{7} \Rightarrow This means 5 seat is filled for every 7 seats capacity

Now, \displaystyle\frac{5}{7} = \displaystyle\frac{25}{35}

Hence, wagon = seat = 35

The seat is always 20% vacant.

So, it can carry maximum 80% passengers.

Hence, maximum passenger

= 35\times 35\times \displaystyle\frac{25}{35}

= 980

## Join Us

Join the discussion and ask any question of maths and reasoning directly to us and other like-minded user just like you!

TinaHow do you you find number of wagon = 35

Team NJPIf 5 seat if filled, seat capacity = 7

So, 25 seat filled = 35 seat capacity

Just do the simple unitary, and you will get the answer.

smorter giremalVery efficiently written article. It will be beneficial to anyone who employess it, as well as myself. Keep doing what you are doing – i will definitely read more posts.